A cartesian equation of a curve is simply finding the single equation of this curve in a standard form where xs and ys are the only variables. To find this equation, you need to solve the parametric …

Feb 3, 2025 · Use the computed normal vector $ (n_1, n_2, n_3) $ to form the equation. Step 4: Expand and Simplify Expand the equation to get it in standard Cartesian form: $$ Ax + By + Cz + D = 0 $$ …

Aug 24, 2018 · Checking an elementary Mathematics book you'll find there is an trigonometric equation (See Marvis's answer). Now if you get $\frac {1} {2}\theta=z$ or $x$ or $y$ or every name you want …

Nov 30, 2019 · The solution won’t be unique, but if all goes well (you haven’t made a mistake and the points aren’t colinear) the solution space will be one-dimensional. That’s to be expected since you …

Nov 18, 2015 · 0 I'm trying to find the cartesian equation of the curve which is defined parametrically by: $$ x = 2\sin\theta, y = \cos^2\theta $$ Both approaches I take result in the same answer:

Sep 16, 2016 · 1 All polar to Cartesian / Cartesian to polar transformations derive from these simple rules r2 = x2 +y2 x= rcosθ y= rsinθ r 2 = x 2 + y 2 x = r cos θ y = r sin θ r= cos2θ r = c o s 2 θ the 4 …

Dec 3, 2017 · 1 You know that your new plane must be parallel to both $ (-3,-3,0)$ and $ (1,2,-1)$. Thus, you want a plane perpendicular to the vector perpendicular to these two vectors, let’s call it …

Apr 25, 2013 · OK, but now let's say, for the sake of argument, that you are insane and wish to generate that spiral from a Cartesian expression. How would you do it, knowing that blind use of arctan will …

Sep 22, 2020 · How to find the cartesian equation of a plane given the vector equation? Ask Question Asked 5 years, 2 months ago Modified 5 years, 2 months ago

Mar 20, 2016 · Parametric: Eliminate the parameter to find a Cartesian equation of the curve. Ask Question Asked 9 years, 8 months ago Modified 9 years, 8 months ago