I have a piece of code here that is supposed to return the least common element in a list of elements, ordered by commonality: def getSingle(arr): from collections import Counter c = Counte...
The first way works for a list or a string; the second way only works for a list, because slice assignment isn't allowed for strings. Other than that I think the only difference is speed: it looks like it's a little faster the first way. Try it yourself with timeit.timeit () or preferably timeit.repeat ().
If your list of lists comes from a nested list comprehension, the problem can be solved more simply/directly by fixing the comprehension; please see How can I get a flat result from a list comprehension instead of a nested list?. The most popular solutions here generally only flatten one "level" of the nested list. See Flatten an irregular (arbitrarily nested) list of lists for solutions that ...
(List<Customer>)(Object)list; you must be sure that at runtime the list contains nothing but Customer objects. Critics say that such casting indicates something wrong with your code; you should be able to tweak your type declarations to avoid it. But Java generics is too complicated, and it is not perfect. Sometimes you just don't know if there is a pretty solution to satisfy the compiler ...
For example list and start of containers are now subcommands of docker container and history is a subcommand of docker image. These changes let us clean up the Docker CLI syntax, improve help text and make Docker simpler to use. The old command syntax is still supported, but we encourage everybody to adopt the new syntax.
@Sandy Chapman: List.of does return some ImmutableList type, its actual name is just a non-public implementation detail. If it was public and someone cast it to List again, where was the difference? Where is the difference to Arrays.asList, which returns a non-public List implementation, that throws an exception when attempting add or remove, or the list returned by Collections ...
Possible Duplicate: Get difference from two lists in Python What is a simplified way of doing this? I have been trying on my own, and I can't figure it out. list a and list b, the new list should
Stephane: Let me rephrase it: if x in list is not the thing that people complain not being a built-in function. They complain about the fact that there is not explicit way to find the first occurrence of something in a list that matches a certain condition. But as stated in my answer, next() can be (ab)used for that. Niklas B. Over a year ago
The second action taken was to revert the accepted answer to its state before it was partway modified to address "determine if all elements in one list are in a second list".
A work around is create a custom_list type that inherits list with a method __hash__() then convert your list to use the custom_list datatype. still better to use built-in types.
